Lets take an example.
Let’s say a construct’s att drop chance is 1/80.
If one tesla coil had a chance of 1/800 for dropping att, your chance of getting nothing from 10 coils is (799/800)10 = 0.9987510 = 0.98757007864 . . . = 98.75701%.
So your chance of getting something is 100 - 98.75701 = 1.24299%
Your chance should be 1/80 = 1.25%
Therefore simply dividing the chance by 10 won’t get you the same result.
Previous reasoning
That’s why I said 10√(1/80)
If you do 10√(x)*10√(x)*10√(x)*10√(x)*10√(x)*10√(x)*10√(x)*10√(x)*10√(x)*10√(x)
(That’s 10√(x) to the power of 10)
You get x. So to make your chance of getting something from 10 coils the same as from one construct, you need to make the coil drop chance the tenth root of the construct drop chance.
That’s why I said the tenth root of the att drop chance of constructs. It’s 10√(.<construct att drop chance>)
10√(1/80) = 0.645195 = 64.5195%
##OH DEAR YOU’RE RIGHT.
Hmm…
We want the chance of getting nothing from 10 pillars to be equal to the chance of getting nothing from a construct, so 10√(79/80) = 0.9987429 = 99.87429%
100 - 99.87429% = 0.125708742%
How to put this in general form…
(1 - 10√(1 - (<construct att drop chance>/100))) * 100
There we go. That should be the drop chance.
What we had before was the chance if we wanted the chance to get 10 pots from 10 pillars to be equal to the chance of getting 1 pot from a construct. :p
###TL;DR: I messed up, the chance should be (1 - 10√(1 - (<construct att drop chance>/100))) * 100
[EDIT:small fix]
