the other thread is locked now, but i’m doing some advanced complex numbers and i’m not afraid of y’all so come at me
please dont hurt me
the other thread is locked now, but i’m doing some advanced complex numbers and i’m not afraid of y’all so come at me
please dont hurt me
2,584,638,177,028,909,832,402,752,497,738,496,030,749,051,342,793,470,811,807,579,926,254,317,166,708,238,543,907,385,347,272,729,042,218,467,682,093,602,422,256,100,818,152,430,935,624,226,377,811,558,825,040,752,508,590,530,292,562,139,641,442,222,218,097,494,964,418,847,092,820,386,914,489,180,578,101,563,130,793,750,097,361,728,926,290,149,192,943,280,561,100,494,496,433,330,266,763,884,299,382,636,767,666,000,498,737,360,894,746,277,833,513,334,845,072,127,211,207,759,966,888,239,920,563,675,233,525,231,978,937,102,582,233,014,028,629,295,631,298,552,497,947,603,966,492,517,443,304,245,188,665,479,167,411,470,719,404,661,678,374,202,249,177,057,036,643,863,610,713,484,287,933,047,949,137,824,473,419,256,922,149,347,851,451,162,676,464,719,858,028,212,552,927,548,308,603,532,863,923,163,353,287,201,212,407,209,387,862,576,438,672,668,196,168,471,245,535,786,845,682,424,103,803,665,628,165,630,358,381,725,438,762,439,220,136,781.60898791034665119867
give or take a few trillion
-.-
1,730,117,086,095,357,261,346,656,428,259,594,485,009,226,296,937,439,917,099,818,185,735,683,984,963,428,791,544,547,705,390,638,035,398,454,707,136,690,735,520,715,945,842,253,985,022,113,289,881,672,827,601,319,269,956,255,621,106.76117032152823229317
I got 1.730117e+174 which is the same as your answer I think…
(I used the google caclulator lol)
your problem:
solving:
u-sub -
thus you get
which then gives
sub u back in and get
!_!
your problem:
-x - 6y = 21
5x - 12y = -21
solving:
-2x - 12y = 42
5x - 12y = -21
-7x = 63
x = -9
-45 - 12y = -21
-12y = 24
y = -2
y = -2 and x = -9
u-sub: u = 1+tanx
du = sec2x dx
thus going back to the original equation:
erm actually never done log before, i’ll assume u mean log10
ok uhhh this is lookin bad ima just take a step outta here
int by parts:
integral of log10x is the integral of lnx/ln10 which gives ln10 * integral of lnx which is xlnx - x + C
which then gives ln10(xlnx-x+C)
w’=log10u w=ln10(ulnu-u+C)
v=1/(u-1)2 v’ = -2/(u-1)3
= ln10(ulnu-u)/(u-1)2 + 2ln10(ulnu-u+c)/(u-1)3du
i hope for my own sanity that u wrote this problem wrong .-.
Doesn’t log automatically refer to ln in calculus? Also, I just google difficult calculus problems and went to the last one XD
dear god lol all i know is that if i did it some other way i’d be in the realm of stackin int by parts and complex numbers and whatnot and it hurts my brain